6x^2+82x-28=0

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Solution for 6x^2+82x-28=0 equation: 



6x^2+82x-28=0

a = 6; b = 82; c = -28;
Δ = b2-4ac
Δ = 822-4·6·(-28)
Δ = 7396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7396}=86$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(82)-86}{2*6}=\frac{-168}{12}
=-14
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(82)+86}{2*6}=\frac{4}{12}
=1/3
$

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